Theoretically, it should be possible to land before taking off (if you go on a fast enough airplane between two cities close to a time-zone boundary).

Practically, are there any such flights, even if they were on opposite sides of the international date line?

  • 6
    Depends on how you account for time. I don't know if this is constructive or even relevant here. I would say skeptics.SE would be better suited for this.
    – Karlson
    Mar 12, 2013 at 18:11
  • 2
    Yes, especially if you cross the International Date Line.
    – waiwai933
    Mar 12, 2013 at 18:12
  • @waiwai933 Only if you account for time as local in the timezone where you are currently located. If accounting in UTC it's not and if accounting locally in timezone of origin it is not in most cases.
    – Karlson
    Mar 12, 2013 at 18:17
  • 17
    @Karlson I am fairly confident that the OP is not asking if there are any commercially available flights that permit backwards time travel.
    – waiwai933
    Mar 12, 2013 at 18:21
  • 1
    It is physically impossible to land before taking off.
    – gerrit
    Mar 12, 2013 at 20:17

5 Answers 5


I think just about every flight east across the international date line would qualify.

OZ202 departs 4:30p Tuesday, arrives 11:30a Tuesday

  • If you consider time as local only
    – Karlson
    Mar 12, 2013 at 18:51
  • 20
    @Karlson Well if you consider time by an absolute standard, then it is obviously impossible according to the laws of physics.
    – choster
    Mar 12, 2013 at 18:52
  • Sorry, I did not see that this was already hashed out in the comments.
    – choster
    Mar 12, 2013 at 18:53
  • That was exactly my point and generally it should be reflected in the question, which as it stands seems to be questioning the theory of relativity.
    – Karlson
    Mar 12, 2013 at 18:56

I'm interpreting this question as "Are there flights whose scheduled local arrival time is numerically earlier than scheduled local departure time?" All other interpretations appear to be silly(ier).

This will be satisfied by any flight of less than one hour duration which crosses a time zone boundary westbound. I thought of looking at flights into Chicago: it is near the edge of the Central time zone, but many nearby cities are in the Eastern time zone. I looked at a United Airlines timetable to find short flights from Chicago to destinations to the east, then looked up the corresponding westbound return flights.

The shortest such flight I found was United 5848 which departs South Bend, Indiana (SBN) at 4:33 PM EDT and arrives at Chicago O'Hare (ORD) at 4:20 PM CDT, a duration of 47 minutes. It only operates Saturdays. Recent FlightAware data suggests that SBN-ORD flights may have an actual flying time as short as 18 minutes. The airports are only 135 km (84 mi) apart.

There were other sub-hour flights from South Bend, as well as Muskegon, MI (MKG), but not as short as UA5848. Intriguingly, there are flights to Chicago from Fort Wayne, IN (FWA) and Grand Rapids, MI (GRR) scheduled for exactly one hour, so in terms of local time they arrive at the same time as they leave. An example is United 5345 which departs Fort Wayne at 4:25 PM EDT and arrives Chicago at 4:25 PM CDT.

American Airlines also has Chicago as a hub and had sub-hour flights from Fort Wayne and Kalamazoo, MI (AZO).

  • wow you can travel back in time :)
    – crenate
    Mar 13, 2013 at 19:52
  • 1
    There are similar westbound flights out of Atlanta (which is in the Eastern time zone but very near Central time.) For example Delta 1988 departs from Atlanta, GA at 9:36 AM EDT and arrives at Birmingham, AL 56 minutes later, at 9:32 AM CDT. Mar 21, 2016 at 13:57

Yes, you can. And you can so so without an aircraft.

@Gagravarr's answer is closest to correct in real physical terms of any answer given.
The following is based on his deeply insightful response. I'm an engineer.
He is obviously [tm] correct in concept, but did not carry his point to its obvious conclusion. I do.
Non-engineers may find themselves querying the validity of this "solution" :-).

Time zones are artificial man made constructs which quantize the gradual variation of real local time as you progress around the globe. The time where you are at any moment IS the real time. To land before you took off you have to land at a place where the real time is earlier than the real time was when you took off.

  • As a given real clock-time travels around the earth with the rotational speed at that point, you need to travel faster than the rotational speed to decrease your current local time.

  • The earth rotates at about 1000 mph rotational velocity at the equator. So, at the equator, an aircraft travelling East at >= 1000 mph will have the real local time decrease as it flies. [I'll use 1000 mph as rotational speed at the equator to make the sums tidier. Actual speed is about 1040.4 mph and what this actually means gets a bit complex as discussed here Earth's Rotation - Wikipedia. 1000 mph is close enough for us.

  • However, that's at the equator.
    As you leave the equator and travel pole-wards you can achieve the same effect at lower velocities.

  • At a lattitude of N degrees North (or South) the rotational velocity, and so the velocity required to "stop time" is

V_time-stop = 1000 x cos(latitude) mph (latitude in degrees).

  • So at 50 degrees South (bottom of NZ) V time_stop = 1000 x cos(50) = 640 mph.

  • At Severnaya Zemlya at 75 degrees North (near the site of the Tsar Bomba) V timestop = 260 mph.

  • At US McMudro base in Antarctica at 77.88S it's ~= 210 mph and
    at Russian Vostok Station at 78.45S it's ~= 200 mph.

An operation Deepfreeze Hercules out of Christchurch on final into McMurdo IF flying due East will be experiencing decreasing real time if travelling at over about 210 mph groundspeed. (Add 4% if you want a slightly more accurate figure). The Russians (and anyone else) at Vostok have it just slightly easier.

Finally, at Amundsen-Scott station AT the South Pole if you walk the short distance to the actual pole, then

  • touch the marker with you RIGHT hand and

  • maintain contact while you jump along arcs of a circle around the pole marker

  • so that you rotate around the marker,

you will land some hours ahead of when you "took off' at every jump.

An added perspective. China operates a single time zone across the whole country - "Beijing time". In eg Urumqi or Kashgar the time is several hours later than it "should" be. Travel out of Western China to any surrounding country and as you cross the border you will "arrive" in the other country several hours before you left China - and no dateline involved.

Then there's Greenwich ... :-)


Not since Concorde stopped flying it hasn't.

British Airways' advertising slogan for a while for Concorde was Arrive before you leave. Between London or Paris and New York, you'd sit in a seat rather like this one, sip champagne, eat a little, and about 3 hours later arrive in Paris, "before" you'd left!

(For this answer, I'm defining "before" as the plane going faster than the revolution of the earth, allowing you to get ahead of the local solar time. This gets easier the closer to the poles you get!)

  • 5
    Well if you accept that fuzzy definition of time, multiple flight still manage to do just that on daily base between mainland Europe and the UK, or Spain and Portugal.
    – user141
    Mar 12, 2013 at 18:59
  • Actually if you're crossing an international date line on a flight < 12 hours your local time will be earlier @landing then your local departure time.
    – Karlson
    Mar 12, 2013 at 19:00
  • Wrong. There are a number of short-distance flights in Europe which cross a time zone but take less than one hour.
    – vsz
    Mar 13, 2013 at 4:00
  • 4
    That's beating a timezone though, not beating the sun, the former being much easier...
    – Gagravarr
    Mar 13, 2013 at 11:09
  • @Gagravarr 's answer is closest to correct in real physical terms of any given. Time zones are artificial man made constructs which quantize the gradual variation of time as you progress around the globe. The earth rotates at about 1000 mph rotational velocity at the equator. At a lattitude of N degrees North (or South) the rotational velocity is 1000 x sin(90-lattitude) So at 50 degrees South (bottom of NZ) V time_stop = 1000 x sin((90-50) = 640 mph. At Severnaya Zemlya ay 75 degrees North (near the site of the Tsar Bomba) V timestop = 260 mph. Mar 13, 2013 at 12:01

As others have said most any flight eastbound across the international date line lands before it takes off. Being an American married to a Chinese I've taken plenty of such flights. Once we even managed to take off and land AGAIN before the original takeoff.

However, it's also possible to do without the date line. I've done it once but it was so long ago I don't recall the city pair other than it's between capitals in Europe. ~45 minute flight that went one time zone west.

There's also another case that can produce a substantial jump. China operates all on one time zone but it really stretches across several time zones. A flight from western China to a neighbor would likely go back in time.

  • One possibility for that flight would be Helsinki to Stockholm. Nov 29, 2018 at 1:32
  • @MichaelLugo I'm certain it wasn't that pair as I've never been to either of those cities. I'm pretty sure the eastern half of the pair was behind the Iron Curtain. Nov 29, 2018 at 4:42

Not the answer you're looking for? Browse other questions tagged or ask your own question.